A Car Engine Having Efficiency Of 10% As Heat Engine Is Used As A Refrigerator. If The Work Done On The System Is 10 Joules The Amount Of Energy Absorbed From The Reservoir At Lower Temperature Would Be How Much?


Answer:
The efficiency is the useful work divided by the total work. If 10J of work is done and only 10% is adjectives, then the amount of heat moved out of the reservoir will be ...
10% * 10 J = 1 J


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